Question

Find the value of 2X3_3x+ROOt by 5 when x is - 3​

Answer 1

Answer:

2$x^{3}$-3x+$\sqrt{5}$

when x= -3

2$(-3)^{3}$-3 x -3+$\sqrt{5}$

2 x -27+9+$\sqrt{5}$

-54+9+$\sqrt{5}$

= -45+$\sqrt{5}$ = $\sqrt{5}$-45

Step-by-step explanation: