find the value of 2x⁴+3x³+2ax²+3x+6 is divisible by 1-2x
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1-2x=0
x=1/2
2x^4+3x^3+2ax^2+3x+6=0
2 (1/2)^4+3(1/2)^3+2(a)(1/2)^2+3 (1/2)+6=0
1/8+3/8+a/2+3/2+6=0
1+a+3+12/2=0
16+a=0
a=-16
x=1/2
2x^4+3x^3+2ax^2+3x+6=0
2 (1/2)^4+3(1/2)^3+2(a)(1/2)^2+3 (1/2)+6=0
1/8+3/8+a/2+3/2+6=0
1+a+3+12/2=0
16+a=0
a=-16
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