Math, asked by dnsjuw, 11 months ago

find the value of 2y(-y²+3y-4)

Answers

Answered by kcpd

2

Answer:

2y(-y²+3y-4)=0

-y²+3y-4=0

y²-3y+4=0

y²+y-4y+4=0

-y(y-1)-4(y-1)=0

(-y-4)(y-1)=0

y=1,4

Answered by pradeepsingh0438

0

Answer:

-2y^3-2y

Step-by-step explanation:

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