Question

find the value of(3^0+4^_1)×2^2

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Answer 1

Answer:

The Value of ($(3^{0}+4^{1})$)×$2^{2}$ is 20

Step-by-step explanation:

($3^{0}+4^{1}$)×$2^{2}$

= (1 + 4) x 4    [∵ $a^{0}=1,a^{1} = a,a^{2}=a*a$]

                      [∴$3^{0}=1,4^{1}=4,2^{2}=4$]

= 5 x 4

= 20

∴ Required value is 20

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