Math, asked by Vishishtsam, 1 year ago

find the value of √3-²

Answers

Answered by harendrachoubay
118

The value of \sqrt{3}^{-2}=\dfrac{1}{3}

Step-by-step explanation:

We have,

\sqrt{3}^{-2}

To find, the value of \sqrt{3}^{-2}=?

\sqrt{3}^{-2}

=\dfrac{1}{\sqrt{3}^{2}}

Using the identity,

a^{-m} =\dfrac{1}{a^{m}}

=\dfrac{1}{\sqrt{3}\times \sqrt{3}}

=\dfrac{1}{3}

[ ∵ \sqrt{3} \times\sqrt{3}=3]

∴The value of \sqrt{3}^{-2}=\dfrac{1}{3}

Thus, the value of \sqrt{3}^{-2}=\dfrac{1}{3}

Answered by Agrim4547
8

Answer:

12

Step-by-step explanation:

Answer:

12

Step-by-step explanation:

2root3*2root3

=4×3

=12

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