find the value of (3+2/i)(i6-i7)(1+i11)
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Answer:
(3 + 2 / i)(i^6 - i^7)(1 + i^11) = 6i + 4
Step-by-step explanation:
we are given that
(3 + 2 / i)(i^6 - i^7)(1 + i^11)
= (3 + 2i / i²)(i^6 - i^7)(1 + i^11)
= (3 - 2i)(-1 + i)(1 - i) ∵ i^6 = -1 , i^7 = -i , i^11 = -i , i² = -1
= (3 - 2i)(-1)(1 - i)(1-i)
= ( 2i - 3 )(1 - i)²
= ( 2i - 3 )(1² - 2i + i²)
= ( 2i - 3 )(1 - 2i - 1) ∵ i² = -1
= ( 2i - 3 )(- 2i )
= 6i - 4i² ∵ i² = -1
= 6i + 4
Hence
(3 + 2 / i)(i^6 - i^7)(1 + i^11) = 6i + 4
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