Question

Find the value of (3+3√2 ) * 0/2​

Answer 1

Answer:

Let the value of √(3–2√2) is (√x - √y) , accordingly :-

(√x - √y)^2 = (3 - 2√2).

or, x + y -2√(x.y) = 3 - 2√2.

or, x + y = 3. …………..(1). , x.y = 2. ………………..(2).

Putting y= 3 - x from eqn. (1) to eqn.(2).

x.(3-x) = 2.

or, x^2 -3.x + 2 =0.

or, (x -2).(x-1) = 0.

or, x = 2 , 1.

y = 3 - x.

or, y = 3 - 2 , 3–1.

or, y = 1 , 2.

Thus , the values of √(3–2√2) are (√2 - 1) or, (1- √2). Answer.

Answer 2

Answer:

Please see my first and

Step-by-step explanation:

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