find the value of ((3/4)^-2 ÷ (4/3)^2)^0
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Answer:
3-2 = 1/32 = 1/9 [a-m = 1/ am]
(ii) (-4)-2 = 1/42 = 1/16 [a-m = 1/ am]
(iii) (1/2)-5 = (2/1)5 = 25 = 32 [a-m = 1/ am]
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