Find the value of 3×(-5)⁴×7²
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Answer:
3*(-5)^4*(7)^2
3*(-5)^4*(7)^2=> (-5) ^4= 125
3*(-5)^4*(7)^2=> (-5) ^4= 125=> (7) ^2= 49
3*(-5)^4*(7)^2=> (-5) ^4= 125=> (7) ^2= 49so, 3*125*49
3*(-5)^4*(7)^2=> (-5) ^4= 125=> (7) ^2= 49so, 3*125*49 =>18375
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