Find the Value of ✓3 Cos 23° - Sin23° / 2.
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Answered by
10
LHS= root 3 cos 23 - sin 23
multiplying and dividing 2 in LHS,
2(root 3/2 cos 23 - 1/2sin 23)
since root 3/2 is cos30 and sin 30 is 1/2 so we replace them and write them as
2(cos30 cos23- sin30 sin 23)
therefore it is 2cos53 which is other wise can be written as 2(sin 37)
(cos(90 - theta) = sin theta)
multiplying and dividing 2 in LHS,
2(root 3/2 cos 23 - 1/2sin 23)
since root 3/2 is cos30 and sin 30 is 1/2 so we replace them and write them as
2(cos30 cos23- sin30 sin 23)
therefore it is 2cos53 which is other wise can be written as 2(sin 37)
(cos(90 - theta) = sin theta)
Answered by
25
Hii friend,
✓3 Cos 23° - Sin23°/2
= ✓3 Cos23°/ 2 - 1/2 Sin23°
= Cos30° Cos23° - Sin 30° Sin23°
= Cos(30+23°)
= Cos53° Ans.....
HOPE IT WILL HELP YOU.... :-)
✓3 Cos 23° - Sin23°/2
= ✓3 Cos23°/ 2 - 1/2 Sin23°
= Cos30° Cos23° - Sin 30° Sin23°
= Cos(30+23°)
= Cos53° Ans.....
HOPE IT WILL HELP YOU.... :-)
hardik1213:
Hello
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