Find the value of 3 tan²A - 3 sec²A + 3
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Answered by
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Answer:0
Step-by-step explanation:
We have,
3 tan²A - 3 sec²A + 3
=3(sec²A - 1) - 3sec²A +3
(Since,1+tan²A= sec²A)
=3sec²A - 3 - 3 sec²A +3
=0.
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