Question

find the value of
(3²×4–³)(3²×4³)​

Answer 1

Answer:

Now, (3² × 4⁻³) (3² × 4³)

= 3² × 4⁻³ × 3² × 4³

= (3² × 3²) × (4⁻³ × 4³)

= 3²⁺² × 4⁻³⁺³

= 3⁴ × 4⁰

= 243 × 1

= 243

Rule:

• aᵇ × aᶜ = aᵇ⁺ᶜ

• aᶜ × bᶜ = (a × b)ᶜ

Answer 2

$\huge\underline\mathfrak\purple{Solution}$