Question

find the value of 4/(216)-⅔+1/(256)-¾+2/(243)-⅛​

Answer 1

Answer:

4/(216)⁻²/³ + 1/(256)⁻³/⁴ + 2/(243)⁻¹/⁵

Taking one term at a time, we solve as follows:

4/ (216)⁻²/³ = 4 / (216)⁻²/³ = 4 * 216²/³ = 4 * (6³)²/³ = 4 * 6² = 144

1/ (256)⁻³/⁴ = (256)³/⁴ = (4⁴)³/⁴ = 4³ = 64

2/(243)⁻¹/⁵ = 2 * (243)¹/⁵ = 2 * (3⁵)¹/⁵  = 2 * 3 = 6

4/(216)⁻²/³ + 1/(256)⁻³/⁴ + 2/(243)⁻¹/⁵ = 144 + 64 + 6 = 214

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Answer 2

Step-by-step explanation:

4/(216)⁻²/³ + 1/(256)⁻³/⁴ + 2/(243)⁻¹/⁵

Taking one term at a time, we solve as follows:

4/ (216)⁻²/³ = 4 / (216)⁻²/³ = 4 * 216²/³ = 4 * (6³)²/³ = 4 * 6² = 144

1/ (256)⁻³/⁴ = (256)³/⁴ = (4⁴)³/⁴ = 4³ = 64

2/(243)⁻¹/⁵ = 2 * (243)¹/⁵ = 2 * (3⁵)¹/⁵  = 2 * 3 = 6

4/(216)⁻²/³ + 1/(256)⁻³/⁴ + 2/(243)⁻¹/⁵ = 144 + 64 + 6 = 214

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