find the value of 4/(216)^-2/3 +1/(256)^3/4+2/234-1/5
Answers
Answered by
0
Answer:
Let
a=
(216)
3
−2
4
+
(256)
4
−3
1
+
(243)
5
−1
2
=
6
−2
4
+
4
−3
1
+
3
−1
2
=4(6
2
)+1(4
3
)+2(3)
a=144+64+6=214
∴
(216)
3
−2
4
+
(256)
4
−3
1
+
(243)
5
−1
2
=214
Similar questions
Accountancy,
1 month ago
Music,
1 month ago
Math,
1 month ago
Chemistry,
3 months ago
Political Science,
9 months ago
English,
9 months ago