Question

Find the value of 4/(216)^-2/3+1/(256)^-3/4+2/(343)^-1/5

Answer 1

Please find the attached image of solution.

Answer 2

214

Step-by-step explanation:

Given,

$\frac{4}{216^{\frac{-2}{3} } }$ + $\frac{1}{256^{\frac{-3}{4} } }$ + $\frac{2}{243^{\frac{-1}{5} } }$

Using exponent property:

$\frac{1}{a^{-1} } }$ = a

4 $(216)^{\frac{2}{3} }$ + 1 $(256)^{\frac{3}{4} }$ + 2 $(243)^{\frac{1}{5} }$

4 $(6^{3} )^{\frac{2}{3} }$ + 1 $(4^{4} )^{\frac{3}{4} }$ + 2 $(3^{5} )^{\frac{1}{5} }$

Dividing the numbers in exponent:

4 (6)² + 1 (4)³ + 2 (3)

(4 × 6 × 6) + (4 × 4 × 4) + (2 × 3)

(144) + (64) + (6)

144 + 64 + 6

214

Learn more:

Factorise the following

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