Question

Find the value of 51² -49²​

Answer 1

Using: a²-b²=(a+b) (a-b)

(51+49) (51-49)

100 × 2

200.

Answer 2

Here we are given an expression 51² -49²​

We have to find the value of the expression

For this, we will have to use the identity

$(a^{2} -b^{2} )= (a+b)(a-b)$

According to the question, a = 51 and b = 49

51² -49²​ = (51 + 49)(51 - 49)

              =100 - 2

               = 98

The value of  51² -49²​ will be 98