Question

find the value of (6^-1-8^-1)^-1

Answer 1

Solution:

Given&To find: the value of
(6^-1-8^-1)^-1
$(6^{-1}-8^{-1})^{-1}$
= $( \frac{1}{6} - \frac{1}{8} ) ^{-1}$
= $( \frac{8-6}{(8)(6)})^{-1}$
= $( \frac{2}{48}) ^{-1}$
=$(\frac{1}{24})^{-1}$
=$\frac{24}{1}$
=$24$ 
 
                        Hope it helps

Answer 2

(6^-1-8^-1)-1
=(1/6-1/8)^-1
=(4-3/24)^-1
=(1/24)^-1
=1/1/24
=24