find the value of
√6+√6+√6+
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Answer:
Letx=6+6+6+6+...∞
On squaring both sides,
x2=6+6+6+6+6+...∞
x2=6+x
x2−x−6=0
x=2(1)1±12−4×1×(−6)
x=21±25=21±5
∴x=3 or x=−2
Since a negative number cannot be under root, hence x=3
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