Question

find the value of
√6+√6+√6+​

Answer 1

Answer:

Letx=6+6+6+6+...∞

On squaring both sides,

x2=6+6+6+6+6+...∞

x2=6+x                            

x2−x−6=0

x=2(1)1±12−4×1×(−6)

x=21±25=21±5

∴x=3 or x=−2

Since a negative number cannot be under root, hence x=3

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