Question

How can three resistors of resistances 2Ω, 3 Ω, and 6Ω be connected to give a total resistance of (i) 4 Ω, (ii) 1 Ω ?​

Answer 1

Answer:

To obtain a total resistance of 4 Ω from three resistors of given resistances, Firstly, connect the two resistors of 3Ω and 6Ω in parallel to get a total resistance of 2Ω which is less than the lowest individual resistance. Hence, the total resistance of the circuit is 4 Ω. ... ⇒ 1/R = 1 Ω.

Explanation:

hope it was help full

Answer 2

Explanation:

given,

R1=2ohm

R2=3ohm

R3=6ohm

a) when R2 &R3 are connected in parallel with R1in series we get

1/R=1/R2+1/R3

1/R=1/3+1/6

1/R

=1/2R=20hm