find the value of 60×10³ joule/hour on a system whose fundamental units are 100g 100mm and half minute
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solution:
Here, n1=100J
M1=1kg,L1=1m,T1=1s
n2=?M2=100g,L2=10cm,T2=30s
An energy = [ML2T-2]∴a=1,b=2,a=-2
n2=n1(
M1
M2
)1(
L1
L2
)2(
T1
T2
)-2
=100(
1kg
100g
)-1(
1m
10cm
)2(
1s
30s
)-2
=100×10×102×30×30
n2=9×107 new units of energy
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