Question

find the value of (61)² by using proper identity​

Answer 1

Answer:

by using (a+b)²=a²+b²+2ab

(61)²

(60+1)²

(60)²+(1)²+2×60×1

3600+1+120

3721

you are also using this identity (a-b)²=a²+b²-2ab

(100-39)² and your answer is 3721

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