find the value of 625x^2 +676y^2 if 25x-26y=16 and xy=7.
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Hi ,
It is given that ,
xy = 7 ------( 1 )
25x - 26y = 16 ----( 2 )
Squaring on both sides of the
equation ( 2 ),
( 25x - 26y )² = 16²
( 25x )² + (26y)²-2×25x× 26y = 256
625x² + 676y² - 1300xy = 256
625x² + 676y² - 1300 × 7 = 256
625x² + 676y² - 9100 = 256
Therefore ,
625x² + 676y² = 9100 + 256
= 9356
I hope this helps you.
: )
It is given that ,
xy = 7 ------( 1 )
25x - 26y = 16 ----( 2 )
Squaring on both sides of the
equation ( 2 ),
( 25x - 26y )² = 16²
( 25x )² + (26y)²-2×25x× 26y = 256
625x² + 676y² - 1300xy = 256
625x² + 676y² - 1300 × 7 = 256
625x² + 676y² - 9100 = 256
Therefore ,
625x² + 676y² = 9100 + 256
= 9356
I hope this helps you.
: )
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