Math, asked by priyathomas9812, 1 year ago

Find the value of (64)^2 +root 3 32768

Answers

Answered by BharatSabh
4

 \sqrt[3]{32768}  =  \sqrt[3]{ {2}^{15} }  =  {2}^{15 \div 3}  =  {2}^{5} = 32 \\  {64}^{2}   =  ({ {2}^{6} })^{2}  =  {2}^{6 \times 2}  =  {2}^{12}  = 4096 \\  {64}^{2}  +  \sqrt[3]{32768}  = 4096 + 32 = 4128
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