find the value of 64x^3 - 125y^3 if 4x-5y=16 and xy=12
Answers
Answered by
1
Answer:
Answer
4x−5y=16
Cubing on both sides
⇒(4x−5y)
3
=(16)
3
⇒64x
3
−125y
3
−3×4x×5y(4x−5y)=4096
⇒64x
3
−125y
3
−60xy(4x−5y)=4096
⇒64x
3
−125y
3
−60(12)(16)=4096
⇒64x
3
−125y
3
−11520=4096
⇒64x
3
−125y
3
=15616
Answered by
0
Answer:
64x³ - 125y³ = (4x-5y)³ + 3(4x)(5y)(4x-5y)
= (16)³ + 3(4)(5)(12)(16)
= 4096 + 11520
= 15616.
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