Math, asked by bandubabu, 1 year ago

find the value of √(75 - 12 √(21) , the root is under the whole term

Answers

Answered by aryansehgal201
5
 \sqrt{75-12 \sqrt{21} }
Here  12 \sqrt{21}=2 \sqrt{756}
making factors of   2 \sqrt{756}
 \sqrt{ \sqrt{12}  ^{2}  + \sqrt{63}  ^{2}    -2  \sqrt{(12)(63)} }
using (a-b)^2 identity
 \sqrt{ (\sqrt{12} - \sqrt{63}) ^{2} }
\sqrt{12} - \sqrt{63

bandubabu: ok.. thanks
aryansehgal201: welcome......did you get or not :P
bandubabu: still no
bandubabu: but i will try
aryansehgal201: maths cannot be explained by texting i would recommend you to ask the explanation from your teacher
bandubabu: teacher only gave hw
aryansehgal201: In RD sharma and Pradeep their are similar problems you can practice from it
Anonymous: Lol
bandubabu: why lol
Anonymous: Ntng,....urke
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