find the value of [{(-8/17)²}³]⁰ =
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3÷3-²×(3 power 0--3-¹)
=3/3-²×(-1/3¹). [3 power 0=1]
=3-¹-²×(-1/3¹)
=3-¹×(-1/3¹)
=3-¹-¹×(-1)
=3-²×(-1)
=-3-² or(-1/3)²
:. -3-² is in exponent form.
And the value of (-1/3)²
=-1×-1/3×3
=1/9
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=3/3-²×(-1/3¹). [3 power 0=1]
=3-¹-²×(-1/3¹)
=3-¹×(-1/3¹)
=3-¹-¹×(-1)
=3-²×(-1)
=-3-² or(-1/3)²
:. -3-² is in exponent form.
And the value of (-1/3)²
=-1×-1/3×3
=1/9
Please Mark as Brain list
Answered by
0
Answer:
the answer of this question is zero
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