Question

find the value of (-8b^2+4b-8)+(-2b^2-5b-1), when b =(-173)​

Answer 1

Answer:

(-299126)

Step-by-step explanation:

= (-8b^2+4b-8) + (-2b^2-5b-1)

= [(-8b^2) + (-2b^2)] + [(4b) + (-5b)] + [(-8)+(-1)]

= [-8b^2 - 2b^2] + [4b - 5b] + [-8-1]

= [-10b^2] + [-b ] + [-9]

= -10b^2 - b - 9

Given, b= (-173)

then,

= -10b^2 - b - 9

= [-10(-173)^2] - [-173] - 9

= [-10×29929] + 173 -9

= -299290 +173 -9

= -299126

Therefore , the answer is ( -299126)