Question

find the value of (-8b^2+4b-8)+(-2b^2-5b-1), when b= ?​

Answer 1

Answer:

Step-by-step explanation:

(-8$b^2$+4b-8)+(-2$b^2$-5b-1)

=> -8$b^2$+4b-8-2$b^2$-5b-1=0

=> -8$b^2$-2$b^2$+4b-5b-8-1=0

=> -10$b^2$-1b-9=0

=> 10$b^2$ + b +9 = 0