Question

find the value of (8x+y) (8x-y)​

Answer 1

Answer:

(8x+y)(8x-y) =(8x) ^2-(y) ^2

=64x^2-y^2

Answer 2

SOLUTION

TO DETERMINE

The value of (8x+y) (8x-y)

FORMULA TO BE IMPLEMENTED

We are aware of the algebraic identity that

$\sf {a}^{2} - {b}^{2} = (a + b)(a - b)$

EVALUATION

Here the given expression is

$\sf (8x + y)(8x - y)$

We now apply the formula

$\boxed{ \: \: \: \sf {a}^{2} - {b}^{2} = (a + b)(a - b) \: \: \: }$

Thus we get

$\sf (8x+y) (8x-y)$

$\sf = {(8x)}^{2} - {(y)}^{2}$

$\sf = 64{x}^{2} - {y}^{2}$

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