Question

find the value of 8x³+27y³,if 2x+3y=8 and xy=2​

Answer 1

Answer:

$\green{8x^3+27y^3=416}$

Step-by-step explanation:

$\boxed{given}$

if 2x+3y=8

and xy=2

$\boxed{Tofind}$

$\blue{8x^3+27x^3}$

$\boxed{answer}$

using the identity

$\green{(x+y)^3=a^3+b^3+3xy(x+y)}$

$(2x + 3y) {}^{3} = 8x {}^{2} + 27y {}^{2} + 3(6xy)(2x + 3y)$

putting the values we get

$(8) {}^{3} = 8x {}^{3} + 27y {}^{3} + 6(2)(8)$

$512 = 8x {}^{3} + 27y {}^{3} + 96$

$512 - 96 = 8x {}^{3} + 27y {}^{3}$

$416 = 8x {}^{3} + 27y {}^{3}$

Answer 2

Answer:

Step-by-step explanation:

A