Math, asked by abhisem9348516149, 6 months ago

find the value of
9tan²A-9sec²A=​

Answers

Answered by muskan65282
1

Answer:

answer is -9

Step-by-step explanation:

9(tan^2A-sec^2A)

-9(sec^2A-tan^2A)

-9*1

-9

Answered by pandeynikhil4208
1

Answer:

9

Step-by-step explanation:

9tan²A-9sec²A=

We have an identity that ,

Tan²A-Sec²A=1..............(1)

= 9(tan²A-sec²A) (from 1)

= 9(1)

= 9

Answer is 9

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