Math, asked by jamunashreya, 1 year ago

Find the value of a^3-27b^3 if a-3b =-6, ab = -10

Answers

Answered by singhtani2014
131
a3 - 27b3=?
a-3b=-6
ab=-10
using (a-b)3=a3-b3-3ab(a-b)
          (a-3b)=(a)3-(3b)3-3ab(a-3b)
          (-6)3 =(a)3 - (3b)3 - 3(-10)(-6)    
          a3-27b3 = -216+180
                   ANSWER =a3-27b3 = -36
          
Answered by nikunjsharma2726
80

Answer:

a3 - 27b3=?

a-3b=-6

ab=-10

using (a-b)³=a³-b³-3ab(a-b)

          (a-3b)³ =(a)³-(3b)³- 9ab(a-3b)

          (-6)³ =(a)³ - (3b)³ - 9(-10)(-6)    

          a3-27b3 = -216+540

                   ANSWER =a³ -27b³ = 324

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