Find the value of a abd b in each of 5+2√3/7+4√3=a-6√3
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hope it helps you
Step-by-step explanation:
first rationalise the denominator and then compare it with a-6√3
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Step-by-step explanation:
(5+2√3÷7)+4√3 = a - 6√3
a=[{5+2√3}÷7]+4√3 +6√3 [taking 6√3 to left hand side]
a=[{5+2√3}÷7] +10√3
a=[5+2√3 +70√3]÷7 [LCM]
a=[5+72√3]÷7
a=129.704÷7 [substituting √3 = 1.732]
a=18.529
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