Question

find the value of a and b ,√3+1/√3+1=a+b√3

Answer 1

Root3 +1/ root 3-1
Root3 +1 ×root3 +1/ root3-1×root3 +1
Root3+1× root3+1 show property (a+b) square and root3 -1× root3+1 show property (a+b)(a-b)
Solve it
(root3) square +(1)square +2×root3×1/(root3)square -(1)square
By solving it
3+1+2root3/ 3-1
= 4+2 root3/2
Take 2 common
=2 (2+root3)/2
=we get 2+root3
So, value of a is 2 and b root 3 is root3
Root 3 cancel
So value of b is 1
I think its helpul for you