Question

find the value of a and b​

Answer 1

Step-by-step explanation:

rationalise denominator

Answer 2

$\frac{ \sqrt{2} + \sqrt{3} }{3 \sqrt{2} - 2 \sqrt{3} } \times \frac{3 \sqrt{2} + 2 \sqrt{3} }{3 \sqrt{2} + 2 \sqrt{3} } = a - b \sqrt{3} \\ \\ = > \frac{6 + 2 \sqrt{6} + 3 \sqrt{6} + 6}{18 - 12} = a - b \sqrt{3} \\ \\ = > \frac{12 + 5 \sqrt{6} }{6} = a - b \sqrt{3} \\ \\ = >2 + \frac{5 \sqrt{2}. \sqrt{3} }{6} = a - b \sqrt{3}$

On comparing :

$a = 2 \: and \: b = \frac{ - 5 \sqrt{2} }{6}$

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