Find the value of a and b :
(A) 3+√2/3-√2 = a+b=√2
(B)√11-√7/√11+√7 =a-b√77
(C)7+3√5/3+√5 -7-3√5/3-√5 =a+b√5
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Yeah
Answers
Answered by
4
hi....
(1)3+ _ 3+, 3:82
[Multiplying the numerator and the denominator by (3
3-5
3-8
+2
+45)
— 946242
9-2
_ 11468
11+
“2 a+b
Itis given that
>
“.a=11/7andb=6/7
(2)= ( √11-√77)²/4
by rationalising denominator
11-2√77+7/4
by using identity(a+b)²=a²+b²+2ab
18-2√77/4
adding. 11 and 7
2(9-√77)/4
taking 2 as common
9-√77/2=a-√77b
a=9
b=1/2
(1)3+ _ 3+, 3:82
[Multiplying the numerator and the denominator by (3
3-5
3-8
+2
+45)
— 946242
9-2
_ 11468
11+
“2 a+b
Itis given that
>
“.a=11/7andb=6/7
(2)= ( √11-√77)²/4
by rationalising denominator
11-2√77+7/4
by using identity(a+b)²=a²+b²+2ab
18-2√77/4
adding. 11 and 7
2(9-√77)/4
taking 2 as common
9-√77/2=a-√77b
a=9
b=1/2
its ok
now i am going to leave brainly forever because everyone is irritating over here... they are not helpful
bye
Because there are some annoying people in this app
And I can't tolerate them anymore
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