Find the value of A and B for which each of the following system of linear equation has infinite number of solutions a - 1 X + 3 Y is equal to 2 and 6 X + 1 - 2 B Y is equal to 6 find value of a and b
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first equation is (a-1)x+3y=2
second equation is 6x+(1-2b)y=6
if two equations has infinite solution,
then a1/a²=b1/b2=c1/c2
a-1/6=3/1-2b=2/6
so to find a,
a-1/6=2/6
a-1=2
a=3
to find b,
3/1-2b=2/6
3/1-2b=1/3
3*3=1-2b
9-1=-2b
8=-2b
b=8/-2
b=-4
the value of a is 3 and b is -4
second equation is 6x+(1-2b)y=6
if two equations has infinite solution,
then a1/a²=b1/b2=c1/c2
a-1/6=3/1-2b=2/6
so to find a,
a-1/6=2/6
a-1=2
a=3
to find b,
3/1-2b=2/6
3/1-2b=1/3
3*3=1-2b
9-1=-2b
8=-2b
b=8/-2
b=-4
the value of a is 3 and b is -4
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