find the value of A and B for which the following system of linear equation has infinitely many Solutions 2x+3y=7;(a+b)x+(2a-b)y =21
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Answer:
=b = 1
= a = 5
Step-by-step explanation:
==2/(a+b) = 3/(2a-b)
==2(2a-b) = 3(a+b)
==4a - 2b = 3a + 3b
==a = 5b
==3/(2a-b)=7/21
==63 = 14a - 7b
==63 = 14(5b) - 7b
==63 = 63b
==b = 1
==a = 5(1)
== a = 5
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