find the value of A and B for which x=1/4and x=-2 are the root of equation ax^2+bx-6=0
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Roots of the polynomial ax^2+bx-6 are 1/4 and - 2
When - 2 is the zero
a(-2) ^2+b(-2)-6=0
4a-2b-6=0
4a-2b=6 - - eq1
When 1/4 is the zero
a(1/4)^2+b(1/4)-6=0
डॉ 1/16a+1/4b-6=0
1/16a+1/4b=6 - - eq2
Solving eq1 and eq2 by elimination method, we get a=12 and b=-21
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Step-by-step explanation:
When - 2 is the zero
a(-2) ^2+b(-2)-6=0
4a-2b-6=0
4a-2b=6 - - eq1
When 1/4 is the zero
a(1/4)^2+b(1/4)-6=0
डॉ 1/16a+1/4b-6=0
1/16a+1/4b=6 - - eq2
After solving the two equations, we get a=12 and b=-21
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