Find the value of a and b for which x=3/4 and x= -2 are the roots of the equation ax2+bx-6=0.
Answers
Answered by
5
Answer:
x = 3/4
x = -2
ax2 + bx - 6 = 0
=> a*3/4^2 + b*-2 = 0
=> 3a/4^2 + -2b = 0
=> 3a/4 + -2b = √0
=> 3a + -2b = 0*4
=> 3a - 2b = 0
=> 3a = 0 + 2b
=> 3a = 2b
=> a/b = 2/3
Therefore,
a = 2. ANS.
b = 3. ans.
Answered by
2
the given equation is
so..we have to fill the values of x in the equation.
LCM is equalled to 9
Divide whole equation by 2
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