find the value of a and b from the figure
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Answer:
a=50°
b=80°
Step-by-step explanation:
∠BDC=∠ABD=50° (Alternate interior angles are equal.)
∠BCD=b=180°-2a
in triangle BCD,
∠BCD+∠CDB+∠DBC=180°
=>(180°-2a)+50°+a=180°
=> -2a+a+50°=0
=> a=50°
So, b=180°-2a=180°-100°=80°
HOPE IT HELPS,
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