Math, asked by manjuchowdhary355, 9 months ago

Find the value of a and b from
the following equality
68-485 2 - atbu2​

Answers

Answered by nirmalsingh100855
0

Answer:

a² + b² + c² = 68

a² + b² + c² = 68a + b + c = 15

a² + b² + c² = 68a + b + c = 15use the concept ,

a² + b² + c² = 68a + b + c = 15use the concept ,(a +b + c)² = a² + b² + c² +2(ab+bc+ca)

a² + b² + c² = 68a + b + c = 15use the concept ,(a +b + c)² = a² + b² + c² +2(ab+bc+ca)(15)²= 68 + 2( ab + bc + ca)

a² + b² + c² = 68a + b + c = 15use the concept ,(a +b + c)² = a² + b² + c² +2(ab+bc+ca)(15)²= 68 + 2( ab + bc + ca)225 -68 = 2(ab + bc +ca)

a² + b² + c² = 68a + b + c = 15use the concept ,(a +b + c)² = a² + b² + c² +2(ab+bc+ca)(15)²= 68 + 2( ab + bc + ca)225 -68 = 2(ab + bc +ca)157/2 = ab + bc + ca

a² + b² + c² = 68a + b + c = 15use the concept ,(a +b + c)² = a² + b² + c² +2(ab+bc+ca)(15)²= 68 + 2( ab + bc + ca)225 -68 = 2(ab + bc +ca)157/2 = ab + bc + caab + bc + ca = 78.5

a² + b² + c² = 68a + b + c = 15use the concept ,(a +b + c)² = a² + b² + c² +2(ab+bc+ca)(15)²= 68 + 2( ab + bc + ca)225 -68 = 2(ab + bc +ca)157/2 = ab + bc + caab + bc + ca = 78.5now,

a² + b² + c² = 68a + b + c = 15use the concept ,(a +b + c)² = a² + b² + c² +2(ab+bc+ca)(15)²= 68 + 2( ab + bc + ca)225 -68 = 2(ab + bc +ca)157/2 = ab + bc + caab + bc + ca = 78.5now,(a³ + b³ + c³ -3abc) =( a + b + c )( a² + b² + c² -ab -bc -ca)

a² + b² + c² = 68a + b + c = 15use the concept ,(a +b + c)² = a² + b² + c² +2(ab+bc+ca)(15)²= 68 + 2( ab + bc + ca)225 -68 = 2(ab + bc +ca)157/2 = ab + bc + caab + bc + ca = 78.5now,(a³ + b³ + c³ -3abc) =( a + b + c )( a² + b² + c² -ab -bc -ca)=( 15)( 68 -78.5)

a² + b² + c² = 68a + b + c = 15use the concept ,(a +b + c)² = a² + b² + c² +2(ab+bc+ca)(15)²= 68 + 2( ab + bc + ca)225 -68 = 2(ab + bc +ca)157/2 = ab + bc + caab + bc + ca = 78.5now,(a³ + b³ + c³ -3abc) =( a + b + c )( a² + b² + c² -ab -bc -ca)=( 15)( 68 -78.5)=(15)(-10.5)

a² + b² + c² = 68a + b + c = 15use the concept ,(a +b + c)² = a² + b² + c² +2(ab+bc+ca)(15)²= 68 + 2( ab + bc + ca)225 -68 = 2(ab + bc +ca)157/2 = ab + bc + caab + bc + ca = 78.5now,(a³ + b³ + c³ -3abc) =( a + b + c )( a² + b² + c² -ab -bc -ca)=( 15)( 68 -78.5)=(15)(-10.5)= -157.5 ( answer )

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