Question

Solve these inequalities:- 3x+7<10​

Answer 1

Answer:

Answer:

\huge \boxed{x < 1}x<1

Step-by-step explanation:

First, subtract by 7 both sides of equation.

\displaystyle 3x+7-7 < 10-73x+7−7<10−7

Then, simplify.

\displaystyle 10-7=310−7=3

\displaystyle 3x < 33x<3

Divide by 3 both sides of equation.

\displaystyle \frac{3x}{3} < \frac{3}{3}33x<33

Simplify, to find the answer.

\displaystyle 3\div3=13÷3=1

\huge \boxed{x < 1}x<1 , which is our answer.

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Answer 2

Answer:

1 Add 77 to both sides.

3x=10+7

3x=10+7

2 Simplify 10+710+7 to 1717.

3x=17

3x=17

3 Divide both sides by 33.

x=\frac{17}{3}

x=

3

17