Question

find the value of a and b if √2+1/√2-1 - √2-1/√2+1= a + √2b

Answer 1

(√2+1)^2-(√2-1)^2/(√2-1)(√2+1)=a+√2b.
4×√2×1/2-1=a+√2b [(a+b)^2-(a-b )^2=4ab]
4√2=a+√2b.
so a=0,and b=4.