Math, asked by yukta9612, 1 year ago

Find the value of a and b, if 2 and 3 are zeros of x3+ax2+bx-30

Answers

Answered by michellesebastian98
29

Answer: -10 and 31 respectively-

Step-by-step explanation:

Given that, 2 and 3 are the zeroes of x^3+ax^2+bx-30

p(x)=x^3+ax^2+bx-30

Now,

p(2)=(2)^3+a(2)^2+b(2)-30

=8+4a+2b-30

=4a+2b-22

=2a+b-11

2a+b=11 ...(1)

And

p(3)=(3)^3+a(3)^2+b(3)-30

=27+9a+3b-30

=9a+3b-3

=3a+b-1

3a+b=1 ...(2)

Since 2 and 3 are zeroes of given polynomial.

So, subtracting (1) and (2)

2a+b=11

3a+b=1

_________

-a=10

a=-10

Substituting a=-10 in (1),

2(-10)+b=11

-20+b=11

b=11+20

b=31

Therefore,the value of a and b are –10 and 31 respectively.

Answered by sshankarpoojary17
9

Step-by-step explanation:

2a+b=11

3a+b=1

=-a=10

a=-10

2(-10)+b=11

-20+b=11

b=11+20

b=30

Similar questions