find the value of a and b if 3+√2/3-√2=a+b√2
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3+√2/3-√2 x 3+√2/3+√2 = a+ b√2
(3+√2)^2/ 3-2 = a + b√2
(3)^2 + (√2)^2 + 2(3)(√2) / 1 = a + b√2
9 + 2 + 6√2 / 1 = a+b√2
11+6√2 = a+b√2
a = 11
b = 6√2
(3+√2)^2/ 3-2 = a + b√2
(3)^2 + (√2)^2 + 2(3)(√2) / 1 = a + b√2
9 + 2 + 6√2 / 1 = a+b√2
11+6√2 = a+b√2
a = 11
b = 6√2
meher202004:
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