find the value of a and b if: √3+/√3-1=a+b√3
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√3/{√3-1} = a+b√3
√3(√3+1)/(√3-1)(√3+1)
3+√3/(√3²-1²)
3+√3/(3-1) => (3+√3)/2 => a+b√3
comparing LHS and RHS
3/2 = a
1/2 = b (√3 = 1√3 )
hope this helps
√3(√3+1)/(√3-1)(√3+1)
3+√3/(√3²-1²)
3+√3/(3-1) => (3+√3)/2 => a+b√3
comparing LHS and RHS
3/2 = a
1/2 = b (√3 = 1√3 )
hope this helps
Answered by
3
Hope it helps ya :).....
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