Find the value of a and b if 3+ root 2 upon 3-root 2= a+b root 2
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Answer:
(3+√2)/(3-√2)=a+b√2
rationalize it
then (3+√2)*(3+√2)/(3+√2)*(3-√2)
9+2+6√2=7[a+b√2]
11+6√2=7a+7b√2
a=11/7,b=11/6
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