Question

The volume of 4N HCl and 10 N HCl required to make 1 litre of 6N HCl are

Answer 1

Let x litre of 4N and ( 1 - x ) litre of 10 N salts is required to form 1 litre of 6 N HCl are required.

FORMULA :-

N1 × V1 + N2 × V2 = N ( V1 + V2)

SOLUTION :-

Putting the values , we get

4 (x) + 10 ( 1 - x ) = 6 × 1

=> 4x + 10 - 10x = 6

=> 4 = 6x

=> x = 2/3.

Hence, 2/3 litre of 4N and 1/3 litre of 10N is required.