Question

find the value of a and b if 5+√3/7-4√3=a+b√3​

Answer 1

Step-by-step explanation:

$5 + \sqrt{3} (1 \div 7 - 4) = a + \sqrt{3} b$

than a=5 & b=1/7-4

Answer 2

Answer:

RHS= a+b√3

LHS= 5+2√3/7-4√3

(Rationalizing the denominator)

= 5+2√3/7-4√3*7+4√3/7+4√3

= [5*7+5*4√3+2√3*7+2√3*4√3] / (7) ^2-(4√3) ^2

= here we used (x+y) (x-y) =(x^2-y^2)

= (35+20√3+14√3+24) /(49-48)

= 59+30√3

comparing both sides

LHS=RHS

WHERE, LHS=59+30√3

RHS=A+B√3

AND A=59

B=30

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